Superposition Principle for u(x,t) in Diff. Eq.

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Homework Statement



The function u(x,t) satisfies the equation

(1) [tex]u_{xx}[/tex] = [tex]u_{tt}[/tex] for 0 < x < pi, t > 0

and the boundary conditions

(2) [tex]u_x[/tex](0,t) = [tex]u_x[/tex](pi, t) = 0

Show that (1) and (2) satisfy the superposition principle.

2. The attempt at a solution

I let w(x,t) = au(x,t) + bv(x,t) for two constants a and b.

[tex]w_{tt}[/tex] = [tex]au_{tt}[/tex] + [tex]bv_{tt}[/tex] = [tex]au_{xx}[/tex] + [tex]bv_{xx}[/tex] = [tex]cw_{xx}[/tex], where c is a constant

Have I now showed that w(x,t) satisfies (1)? [tex]w_{xx}[/tex] is not equal to [tex]w_{tt}[/tex] unless c is 1...
 
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You said you let w= au+ bv. What is c? What do you mean by "auxx+ bvxx= c wxx"? I don't see where that comes from.

Perhaps it would be simpler to see if you rewrote the equation as uxx- utt= 0. What is wxx- wtt?