- #1

zealeth

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## Homework Statement

Assume that Vs = 10V , R1 = 1.7Ω , and R2 = 0.50Ω. Find the current I in the figure using the superposition principle.

## Homework Equations

Superposition principle

KCL, KVL

V=IR

Current and voltage dividers

## The Attempt at a Solution

I = I' + I''

First replacing the current source with an open circuit, I have:

(1.7+0.50)*I' = 10 - 2I' using KVL

Solving, I' = 2.38 A

Now replacing the voltage source with a short, I use the current divider to get:

-I'' = 3*0.5/(1.7+0.5) = 0.682 A

I'' = -0.682 A

I = 2.38 - 0.682 = 1.7 A, which is incorrect.

EDIT: Should I have left the dependent source as 2I and solved for I in the final equation, or am I doing something else wrong?

EDIT2: Yes, I did have to leave it as 2I. Got it :)

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