# Supposed to be an easy question about WORK

1. Jul 11, 2006

### mms05

Hi! I need some help with this question:

Jim rides his skateboard down a ramp that is in the shape of a quarter circle with a radius of 5.00 meters. At the bottom of the ramp, Jim is moving at 9.00 m/s. Jim and his skateboard have a mass of 65.0 kg How much work is done by friction as the skateboard goes down the ramp?

What I used was
W=F(force) x r (displacement)
F= mv^2/r
= (65 kg x 9 m/s^2)/(5 m)
= 1035 N

W= (1035 N)(19.6 m) (To find 19.6, I used the circumference equation to find the distance down the ramp)

W= 20,286 J
20.3 kJ

I really do not think this is correct, and I'm trying to figure out what it means by "frictional" force.

Last edited: Jul 11, 2006
2. Jul 11, 2006

### Teegvin

Jim and his skateboard have gravitational potential energy at the top of the ramp, what is it? How much kinetic energy would he have if all of his potential energy were transformed into kinetic? How much kinetic energy does Jim have?

Remember
pe = mgh
ke = (mv^2)/2

3. Jul 11, 2006

### mms05

so i don't have to use the radius of the circular (1/4) ramp at all??

4. Jul 11, 2006

### Teegvin

The radius is also the height from which Jim starts.

5. Jul 12, 2006

### mms05

oh my goodness- I'm so utterly confused... It's just not clicking :(!

6. Jul 12, 2006

### Teegvin

If it were a straight ramp 5m high, would it be easier to understand?

7. Jul 12, 2006

### mms05

yes, i think so- but that wouldn't be the same as it being curved, because the displacement on a curved ramp would be different than that on a straight ramp, no?

8. Jul 12, 2006

### Teegvin

Not necessarily. If the ramp were a 45 degree incline, the displacement would be the same (5m down, 5m over); however, the way I figured this out does not need a displacement.

At the top of the ramp, Jim has no kinetic energy, but he has mgh potential energy. What does he have at the bottom?

9. Jul 12, 2006

### Paquete

mms05 is right, the displacement on a curved ramp would be different than that on a straight ramp, but, in this particular problem you can use a different approach , just like Teegvin said, in order to calculate work.

W = - (Uf - Ui)

where Uf is the final potential energy and Ui is initial potential energy.

10. Jul 12, 2006

### thiotimoline

Find the total energy at the top and at the bottom. The difference in energy is the energy wasted to do work against friction when rolling down the ramp. :)

11. Jul 12, 2006

### mms05

thank you all! :)

12. Jul 20, 2006

### thiotimoline

By conservation of total energy, initial total energy = final total energy + friction.