Surface area of a hemisphere w/ vector calculus

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SUMMARY

The discussion focuses on proving the surface area of the upper hemisphere of radius 'a' using vector calculus, specifically through the evaluation of the surface integral \oint\oint f(x,y,z)dS. Participants agree that the divergence theorem is the most effective approach for this proof. By transforming a volume integral into a surface integral over the bounding surface, one can utilize the divergence operator acting on a vector field to facilitate the calculation. The final result confirms that the surface area is 2\pi a².

PREREQUISITES
  • Understanding of vector calculus concepts, particularly surface integrals.
  • Familiarity with the divergence theorem and its applications.
  • Knowledge of setting up volume integrals in three-dimensional space.
  • Ability to manipulate vector fields and apply the divergence operator.
NEXT STEPS
  • Study the divergence theorem in detail to understand its implications in vector calculus.
  • Practice evaluating surface integrals using examples from vector calculus textbooks.
  • Explore the relationship between volume integrals and surface integrals through practical exercises.
  • Learn about vector fields and how to apply the divergence operator in various contexts.
USEFUL FOR

Students studying vector calculus, particularly those tackling surface area problems in three-dimensional geometry, as well as educators seeking to enhance their teaching methods in calculus.

simpleman008
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Homework Statement


I need help proving how you could use evaluation of the surface integral \oint\oint f(x,y,z)dS to show that the surface area of the upper hemisphere of radius a is 2\pi a2.

So any ideas?


Homework Equations


The teacher mentioned that the divergence theorem would be the best way to go.


The Attempt at a Solution


Besides the hint from my teacher, i haven't gotten anywhere with the problem. It's one that has stumped my entire class. If anyone has any hints at all for where I can start with this problem, I would appreciate it greatly.
 
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so start with the divergence theorem... that tranforms a volume integral, to a surface integral over the bounding surface

so I would try setting up the volume integral first, then see if you can re-write the integrand as the divergence operator acting on a vector field... if you can do that ur pretty much there...
 
sorry read the question incorrectly, i think you would actually do it backwards from what was described
 

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