Surface Area of Cylinder Bounded by x^2 + y^2 = a^2

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SUMMARY

The discussion focuses on calculating the surface area of the cylinder defined by the equation \(y^2 + z^2 = a^2\) and bounded by \(x^2 + y^2 = a^2\). The user attempted to set up a double integral using polar coordinates but faced challenges determining the appropriate boundaries. The integral setup included the expression \(A(S) = \int \int \sqrt{1 + 4y^2 + 4z^2} dA\), indicating a need for clarity on the limits of integration in polar coordinates.

PREREQUISITES
  • Understanding of double integrals in calculus
  • Familiarity with polar coordinates
  • Knowledge of surface area calculations for three-dimensional shapes
  • Basic proficiency in multivariable calculus
NEXT STEPS
  • Review the method for setting up double integrals in polar coordinates
  • Study the derivation of surface area formulas for cylindrical shapes
  • Learn about boundary conditions for integrals in multivariable calculus
  • Explore examples of calculating surface areas of bounded regions
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Students and professionals in mathematics, particularly those studying calculus and geometry, as well as educators seeking to enhance their understanding of surface area calculations for cylindrical structures.

s_engineering
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Find the surface area of the the portions of the cylinder y^2 + z^2=a^2 bounded by x^2 + y^2 = a^2


not really sure how to go about this. tried to set up a double integral and use polar coordinates but don't know what boundaries to use etc.
 
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Welcome to PF!

Hi s_engineering! Welcome to PF! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
this is what I've tried:

fy = 2y; fz=2z

A(S)=int int sqrt{1+4y^2 +4z^2}dA

then I switched to polar coordinates i tired to integrate from theta=0 to pi/2 and r= 0 to a
but didn't get anywhere with this.
 

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