Surface tension calculation problem

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To calculate the surface tension of jelly, the equation Y = F/L can be applied, where F is the force measured by a weighting spring and L is the length of the slide in contact with the jelly. When a microscope slide is dipped into the jelly and pulled out, the force reading on the spring increases until the slide detaches, indicating the force due to surface tension. It's important to note that since the slide has two surfaces, the effective length for the calculation should be doubled, leading to the modified equation Y = F/2L. The length L refers specifically to the portion of the slide that is in contact with the jelly, not the distance from the spring to the slide. This method provides a practical approach to measuring the surface tension of jelly.
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Homework Statement


I need to calculate the surface tension of jelly (gelatine dessert) or jell-o, as it is known in the states.

My textbook defines surface tension as Y=F/L. Is this the equation I would use to calculate surface tension? If so, how?
 
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Take a microscope slide. Attach it to a weighting spring. Dip it in the jelly. Now try to pull it out carefully. Reading in the spring will start increasing. Note down the reading at the moment when the slide detaches from the jelly. Since there are two surfaces on the slide, length of the free surface of the jelly is equal to the double the length of the slide. So according to the definition of the surface tension Y = F/2L.
 
So by reading you mean the length from the top of the spring to the microscopic slide?
 
No. The spring is used to measure the full due to surface tension. Here length is the length of the slide which is in contact with jelly.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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