- #1
Saitama
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Homework Statement
(Ans: ##\pi F/(2L)##)
Homework Equations
The Attempt at a Solution
I am not too much familiar with these type of questions so I don't really how to begin with this. Also, I don't understand the question here. Do we have to consider it in the vertical or horizontal plane? I think its former because the weight of thread is balanced by force of surface tension. If it is so, here's what I have attempted:
For the first case, consider an element of ##Rd\theta## where ##R## is the radius of semicircle. The force due to surface tension can be resolved into two components. From symmetry, we need to integrate only the sine component. (##dF_T## represent the force of surface tension on the small part).
[tex]dF_T=TRd\theta \Rightarrow dF_T\sin\theta=TR\sin\theta d\theta[/tex]
Hence, force due to surface tension is twice the result of the above expression (as there are two sides, I don't know how to put it in words)
[tex]F_T=4TR[/tex]
As the weight of thread is balanced by force due to surface tension, ##mg=4TR##.
In the second case, the force due to surface tension can be separately calculated on each semicircular part by replacing R with R/4 in the above expression for ##F_T##.
[tex]F+mg=4TR/4+4TR/4[/tex]
But solving this gives me a negative value of T.
Any help is appreciated. Thanks!