Symmetry Arguments-a finite cylindrical can

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SUMMARY

The discussion focuses on the electric field generated by a uniformly charged finite cylindrical can. It concludes that at points along the can's central axis (A) and on the plane that bisects the can (B), the electric field is zero due to symmetry. At the exact center of the can (C), the electric field also equals zero, confirming that perfect symmetry and uniform charge distribution lead to no net electric field in these scenarios. The participants emphasize that directionality is more critical than calculating the actual field values, negating the need for integration.

PREREQUISITES
  • Understanding of electric fields and charge distributions
  • Familiarity with symmetry arguments in electrostatics
  • Basic knowledge of cylindrical coordinates
  • Concept of integration in physics (though not necessary for this problem)
NEXT STEPS
  • Study the principles of electric field calculations for symmetrical charge distributions
  • Learn about Gauss's Law and its applications to cylindrical symmetry
  • Explore the concept of electric field directionality in various geometries
  • Investigate the implications of charge distribution on electric field strength
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Students of electromagnetism, physics educators, and anyone interested in understanding the effects of symmetry on electric fields in charged objects.

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Symmetry Arguments--a finite cylindrical can

Homework Statement


Consider a finite cylindrical can shape that has charge uniformly distributed on its surface. Symmetry does allow us to say some things about the electric field of this distribution
A) at points along the can's central axis
B) At points lying on the plane that cuts the can in half perpendicular to its central axis
C) at the can's exact center

What does symmetry tell us in these three cases?

Hint: be sure to consider both the direction of the electric field and on what variables it might or might not depend

Homework Equations


The Attempt at a Solution



Ok, first off, I'm not even sure what I'm supposed to be doing exactly, and is the shape just like a soda can, and the surface the outside not including the top/bottom, ie the body?

a and b to me are confusing. I could see them being zero, but at the same time, they depend on the point you're using on the plane, so I believe you'd have to use an integral, but that'd be a double integral and that seems to complex for this problem.
For A it seems as if it's completely symmetrical across the plane, and it seems to be true for B as well. Meaning there'd be no net charge on either. hmm

c) I'd imagine this has to be zero. Perfect symmetry in all directions and uniform distribution throughout.

So I guess I'm just looking for a start on where I should be heading for and what I should be trying to solve. Thanks, as always, in advance for the great help. Truly appreciated.
 
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Hmm, I interpreted a "can shape" as including the top and bottom. However, I don't think that will affect these questions.

(a) and (b) have more to do with what direction the field points toward. They don't want the actual value of the field, just its direction, so no integration is necessary.

You're correct about (c).
 

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