T and V changing in an isobaric process

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SUMMARY

The discussion focuses on calculating the change in mean temperature and the resulting decrease in thickness of a 1000 to 700 hPa atmospheric layer subjected to radiative cooling at a rate of 5.0e3 J/s/m² for one hour. The first law of thermodynamics is applied, specifically the equation ΔQ = ΔU + W, to analyze the energy transfer. Participants clarify that the energy input is considered work done on the layer, and they emphasize the importance of understanding the relationship between radiative cooling and the heat transfer equations provided.

PREREQUISITES
  • Understanding of the first law of thermodynamics
  • Familiarity with hydrostatic balance in atmospheric layers
  • Knowledge of specific heat capacity (Cp)
  • Ability to perform calculations involving pressure changes (Δp)
NEXT STEPS
  • Calculate the change in mean temperature using the equation ΔT = ΔU/(mCp)
  • Determine the mass per unit area of the atmospheric layer for accurate calculations
  • Explore the implications of radiative cooling on atmospheric stability
  • Investigate the effects of pressure changes on layer thickness in hydrostatic balance
USEFUL FOR

Atmospheric scientists, meteorology students, and anyone studying thermodynamics in relation to atmospheric processes will benefit from this discussion.

BearY
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Homework Statement


Consider a 1000 to 700 hPa layer in the atmosphere that is at rest and is in hydrostatic balance. The layer is subjected to radiative cooling at a rate of 5.0e3 J/s/m2 for one hour.
a) Calculate the change in mean temperature for the layer assuming all energy goes into heating the layer. Hint: We derived the 1st law of thermodynamics on a per mass basis.
b) Find the resulting decrease in the thickness of the layer.

Homework Equations



##\Delta Q = \Delta U + W ##
##\Delta p = -mg##
##\Delta T = \frac{\Delta U}{mC_p}##

The Attempt at a Solution


I am a bit confused and have a few questions.
What does "all energy goes into heating the layer" mean? From what I see, the energy goes in the layer is work done to the layer. Which is ##p\Delta h##
Also, is radiative cooling ##\Delta Q##, or ##\Delta U## only?
We can calculate the mass of a unit column since the layer is in hydrostatic balance.
Then the next step, from what I see, would depend on my understanding of the question.
Did I completely misunderstand the question?
 
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BearY said:

Homework Statement


Consider a 1000 to 700 hPa layer in the atmosphere that is at rest and is in hydrostatic balance. The layer is subjected to radiative cooling at a rate of 5.0e3 J/s/m2 for one hour.
a) Calculate the change in mean temperature for the layer assuming all energy goes into heating the layer. Hint: We derived the 1st law of thermodynamics on a per mass basis.
b) Find the resulting decrease in the thickness of the layer.

Homework Equations



##\Delta Q = \Delta U + W ##
##\Delta p = -mg##
Be careful with units. LS units are force/area. RS units are force. Δp = -(m/A)g where m/A is the mass per unit area of a column of air in the layer.
##\Delta T = \frac{\Delta U}{mC_p}##

The Attempt at a Solution


I am a bit confused and have a few questions.
What does "all energy goes into heating the layer" mean? From what I see, the energy goes in the layer is work done to the layer. Which is ##p\Delta h##
Also, is radiative cooling ##\Delta Q##, or ##\Delta U## only?

We can calculate the mass of a unit column since the layer is in hydrostatic balance.
Then the next step, from what I see, would depend on my understanding of the question.
Did I completely misunderstand the question?
The problem is not stated all that clearly. It appears to me that the radiative cooling relates to heat flow in the form of thermal radiation from the Earth surface. You are to assume that all this heat flow is captured by the layer (ie. Q = 5000 Js-1m-2)

AM
 

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