MHB Table Functions Explained: Help for Understanding

  • Thread starter Thread starter OMGMathPLS
  • Start date Start date
  • Tags Tags
    Functions Table
AI Thread Summary
The discussion focuses on understanding the function rule g(x) = f(-x) + 1. Participants clarify that to find g(-2), one must negate the input, evaluate f at that negated value, and then add 1. The calculations for g(-2) and g(-1) demonstrate this process, yielding results of 0 and 3, respectively. Confusion arises regarding the necessity of using f(x) to determine g(x), but the explanation emphasizes the importance of the negation step. Overall, the thread aims to simplify the understanding of how to apply the given rule for calculating values of g.
OMGMathPLS
Messages
64
Reaction score
0
I do not get what is going on here. Can someone please explain? This is sohard for me to understand. thank you
View attachment 3546
 

Attachments

  • help1.PNG
    help1.PNG
    3.5 KB · Views: 83
Mathematics news on Phys.org
Let's look at the first place where an answer is expected, that is to find $g(-2)$.

We are given the rule:

$$g(x)=f(-x)+1$$

Therefore, we may state:

$$g(-2)=f(-(-2))+1=f(2)+1=-1+1=0$$

Can you try the others in the same way?
 
MarkFL said:
Let's look at the first place where an answer is expected, that is to find $g(-2)$.

We are given the rule:

$$g(x)=f(-x)+1$$

Therefore, we may state:

$$g(-2)=f(-(-2))+1=f(2)+1=-1+1=0$$

Can you try the others in the same way?

Ok so we're including the - we are plugging it in with the negative.
That makes more sense.
 
OMGMathPLS said:
Ok so we're including the - we are plugging it in with the negative.
That makes more sense.

Yes, the rule:

$$g(x)=f(-x)+1$$

tells us to take the input to $g$, change its sign or negate it, and input it to $f$, and then add 1 to that output, and this is the output of $g$. :D
 
so he next values I got were: 0,1,0, -1
 
Let's look at the next one...what did you do to get 0?
 
MarkFL said:
Let's look at the next one...what did you do to get 0?

I'm not sure why we are putting it into the (x) first and then = f(x) if we're trying to find g(x).

Because all we are using from the table is the x so why are we do we even need the f(x)?
 
OMGMathPLS said:
I'm not sure why we are putting it into the (x) first and then = f(x) if we're trying to find g(x).

In order to find $g(x)$, we need to use the given rule:

$$g(x)=f(-x)+1$$

So, we do the following:

1.) Negate the input to $g$.

2.) Pass this negated input to $f$.

3.) Add 1 to the value obtained from $f$.

4.) This is the value of $g$.

So, for the second one, we find:

1.) $$-(-1)=1$$

2.) $$f(1)=2$$

3.) $$2+1=3$$

4.) $$g(-1)=3$$

Or, as I did the first one:

$$g(-1)=f(-(-1))+1=f(1)+1=2+1=3$$ :D
 
MarkFL said:
In order to find $g(x)$, we need to use the given rule:

$$g(x)=f(-x)+1$$

So, we do the following:

1.) Negate the input to $g$.

2.) Pass this negated input to $f$.

3.) Add 1 to the value obtained from $f$.

4.) This is the value of $g$.

So, for the second one, we find:

1.) $$-(-1)=1$$

2.) $$f(1)=2$$

3.) $$2+1=3$$

4.) $$g(-1)=3$$

Or, as I did the first one:

$$g(-1)=f(-(-1))+1=f(1)+1=2+1=3$$ :D

Thank you
 
Back
Top