Taking the Derivative of f(x) = exp(-x^2)

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SUMMARY

The derivative of the function f(x) = exp(-x^2) is correctly calculated using the chain rule. The proper differentiation yields f'(x) = -2x * exp(-x^2). The confusion arose from misapplying the chain rule, where the derivative of the inner function -x^2 must be multiplied by the outer function's derivative. The correct application of these rules leads to the final derivative expression without additional factors.

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  • Familiarity with the chain rule in calculus.
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  • Practice differentiating various exponential functions, particularly those involving polynomials.
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ksle82
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given function f(x) =exp(-x^2)

is f'(x) = -x^2*exp(-x^2), or

f'(x) = -x^2*exp(-x^2)*-2x= 2x^3*exp(-x^2)

just confused what the rules are when taking the derivation of those kind sof function
 
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What's wrong with the chain rule?
 
f^{\prime}(x) = \frac{d}{dx} \left( e^{-x^2}\right) = e^{-x^2}\frac{d}{dx}\left( -x^2\right)

that's the chain rule step, finish it off.
 

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