sin(a+b)/sin(a+c)=[ sin(2b)/sin(2c)]^(1/2)(adsbygoogle = window.adsbygoogle || []).push({});

then prove tan^2a=tanbtanc

I have reached till {tan(a)cos(b)+ sin(b)} * {sin(c)cos(c)}^(1/2)=

{tan(a)cos(c)+sin(c)}* { sin(b) cos(b)}^(1/2)

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# Tan=cos/sin help

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