Tangent Line to Curve of Intersection: Calculating the Normal and Cross Product

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SUMMARY

The discussion focuses on finding parametric equations for the tangent line to the curve of intersection between the cone defined by the equation z=√(x² + 4y²) and the plane given by 3z = x + 2y + 8 at the point (3,2,5). Participants emphasize the importance of calculating the normals to each surface at the intersection point, as these normals are perpendicular to the curve. The cross product of the normals provides the direction of the tangent line to the curve of intersection.

PREREQUISITES
  • Understanding of parametric equations
  • Knowledge of vector calculus, specifically gradients and cross products
  • Familiarity with the equations of surfaces, particularly cones and planes
  • Ability to perform calculations involving square roots and algebraic manipulation
NEXT STEPS
  • Study the method for calculating the normal vector of a surface
  • Learn how to compute the cross product of two vectors
  • Explore the concept of gradients and their geometric interpretations
  • Practice finding tangent lines to curves of intersection in three-dimensional space
USEFUL FOR

Students studying multivariable calculus, particularly those focusing on vector calculus and surface intersections. This discussion is also beneficial for educators looking to enhance their teaching methods regarding tangent lines and curves in three-dimensional geometry.

Yitin
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Homework Statement



Find parametric equations for the tangent line to the curve of intersection of the cone z=√(x2 + 4y2) and the plane 3z = x + 2y + 8 at the point (3,2,5)

2. The attempt at a solution

I was trying to make the two Zs equal to each other, and solve for x or y, but I couldn't get any of them separate. I tried squaring both of them so they would both have things like X2. It didn't work out.
 
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Yitin said:

Homework Statement



Find parametric equations for the tangent line to the curve of intersection of the cone z=√(x2 + 4y2) and the plane 3z = x + 2y + 8 at the point (3,2,5)

2. The attempt at a solution

I was trying to make the two Zs equal to each other, and solve for x or y, but I couldn't get any of them separate. I tried squaring both of them so they would both have things like X2. It didn't work out.

That's enough reason to try a different approach. Remember that the curve of intersection of two surfaces lies in both surfaces. So if you calculate the normal to each surface at a point on the surface, each normal will be perpendicular to the curve at that point. So the cross product of the normals will be tangent to the curve. And gradients are perpendicular to surfaces...
 

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