Tangent to an Ellipse given the slope of the tangent

Click For Summary
SUMMARY

The discussion focuses on determining points on the ellipse defined by the equation x² + 2y² = 1 where the tangent line has a slope of 1. The user struggles with the inverse problem of finding tangent points rather than equations. The solution involves using implicit differentiation to derive the expression for the derivative, y' = (1 - 2x) / (4y), and setting y' equal to 1 to find the corresponding conditions on x and y.

PREREQUISITES
  • Understanding of implicit differentiation
  • Familiarity with the equation of an ellipse
  • Knowledge of slope and tangent lines
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study implicit differentiation techniques in calculus
  • Learn how to derive equations of tangent lines for conic sections
  • Explore the geometric properties of ellipses
  • Practice solving inverse problems in calculus
USEFUL FOR

Students studying calculus, particularly those focusing on conic sections and tangent lines, as well as educators looking for examples of implicit differentiation applications.

Liz226
Messages
2
Reaction score
0

Homework Statement



Determine the points on the ellipse x^2 a 2y^2=1 where the tangent line has a slope of 1

Homework Equations



I'm able to solve problems when given points and asked to find equations of the tangent lines. However, I'm struggling to do the inverse.

The Attempt at a Solution



I've set up the ellipse in an implicit grapher and played around with it to try to find approximately what points it would be, and haven't had much luck, seeing as the implicit graphers don't allow for tracing and such. Setting the equation as y=1x+b seems to be the logical first action; however, I have no clue where to go from there.

Any and all help would be greatly appreciated
 
Last edited:
Physics news on Phys.org
Use implicit differentiation to express y' as a function of x and y. Then set y'=1. What kind of a condition does that give you on x and y?
 
2x+4y(dy/dx)=1
4y(dy/dx)=1-2x
(dy/dx)=(1-2x)/(4y)
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
13
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 11 ·
Replies
11
Views
5K
  • · Replies 7 ·
Replies
7
Views
3K