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Tangential and Radial Acceleration problem!

  1. Feb 9, 2009 #1
    1. The problem statement, all variables and given/known data

    As a locomotive rounds a circular curve of radius 1.80 km, its speed is increasing at a rate of 0.440 m/s2. An instrument in the cab (an accelerometer) indicates that the magnitude of the locomotive's total acceleration at a particular instant is 0.680 m/s2. What is the locomotive's speed at that instant?

    at = 0.440 m/s^2
    a = 0.680 m/s^2
    r = 1800 m



    2. Relevant equations

    a = sqrt(aradial^2 + atangential^2) (1)

    ar = -[(v^2)/r] (2)


    3. The attempt at a solution

    ar = sqrt(0.440^2 + 0.680^2)

    ar= 0.80993

    0.80993 = -[v^2 divided by 1800 m]

    -38.2 But it is showing up in my online assignment that is it wrong :(
     
  2. jcsd
  3. Feb 9, 2009 #2

    LowlyPion

    User Avatar
    Homework Helper

    Welcome to PF.

    I think you almost have it.

    It's just that you maybe have switched the sense of what the problem tells you.

    You have 2 accelerations as you recognized. Tangential acceleration and Centripetal (Radial).

    And the magnitude of their relationship taken together is as I think you figured Radial2 + Tangential2 = Total2

    So far so good. But in the statement of the problem they tell you the Tangential and they tell you the Total, but not the Radial. That's what you need to figure the Tangential velocity.

    Just change the way you figured it.
     
  4. Feb 9, 2009 #3
    thank you!
     
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