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xChrix

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## Homework Statement

As a locomotive rounds a circular curve of radius 1.80 km, its speed is increasing at a rate of 0.440 m/s2. An instrument in the cab (an accelerometer) indicates that the magnitude of the locomotive's total acceleration at a particular instant is 0.680 m/s2. What is the locomotive's speed at that instant?

at = 0.440 m/s^2

a = 0.680 m/s^2

r = 1800 m

## Homework Equations

a = sqrt(aradial^2 + atangential^2) (1)

ar = -[(v^2)/r] (2)

## The Attempt at a Solution

ar = sqrt(0.440^2 + 0.680^2)

ar= 0.80993

0.80993 = -[v^2 divided by 1800 m]

-38.2 But it is showing up in my online assignment that is it wrong :(