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Tangential & normal acceleration derivations

  1. Mar 22, 2010 #1
    I'm trying to understand how my book derives the tangential accelration. I drew a picture because it's kind of confusing to explain.

    From the triangle we get the tangential and normal components of the velocity.

    What my problem is (and I think, and hope, it's something simple that I just can't see) that in the second equation where they find SQ.

    They times they take adjacent x sin(angle) = oposite.

    but isn't sin = oposite/hypoteneuse ??

    shouldn't the formula be adjacent x tan(angle) = opposite = SQ ?

    Attached Files:

    Last edited: Mar 22, 2010
  2. jcsd
  3. Mar 22, 2010 #2
    oops. figured this out. Sorry, this was really silly.
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