B Tangential part of the potential electric field

AI Thread Summary
The tangential component of the electric field near a conductor's surface is zero due to the nature of electrostatics, as any tangential field would cause conduction electrons to move and generate a current. In electrostatics, conductors allow charges to redistribute until the electric field inside the conductor is zero, resulting in a vanishing tangential field at the surface. The normal component of the electric field can be non-zero because the conduction electrons are bound to the conductor. If the external electric field is strong enough to free these electrons, it leads to current flow, moving the situation outside the realm of electrostatics. Thus, the behavior of the electric field components is crucial for understanding electrostatic conditions around conductors.
FrankygoestoHD
Messages
4
Reaction score
1
Good afternoon to everybody. I have may be a stupid question according to the tangential part of the electric field near the surface of the conductor. Why is it zero? The normal part is zero on the distance of Debye cause of screening. But is this situation the same for horizontal direction cause of the charge, pulled by this part of the field and no place for emission of electron to another place?
 
Physics news on Phys.org
I think you talk about electrostatics. Then indeed the electric field has a potential and the tangent component of it must vanish, because by definition a conductor consists of a material containing charges (usually electrons, at least for metals) that can move quasi freely within the material. This means that if there where a component of the electric field tangential to the surface of a conductor these conduction electrons would be set into motion due to the electric force in that direction, and you'd have an electric current flowing, but then you are out of the realm of electrostatics. The normal component of the electric field can be non-zero, because the conduction electrons are bound to the conductor. Of course, if you make the external electric field too strong you can free those electrons overcoming the binding energy, but then you also leave the realm of electrostatics, because again an electric current would flow.
 
  • Like
Likes rudransh verma, FrankygoestoHD, Keith_McClary and 1 other person
vanhees71 said:
I think you talk about electrostatics. Then indeed the electric field has a potential and the tangent component of it must vanish, because by definition a conductor consists of a material containing charges (usually electrons, at least for metals) that can move quasi freely within the material. This means that if there where a component of the electric field tangential to the surface of a conductor these conduction electrons would be set into motion due to the electric force in that direction, and you'd have an electric current flowing, but then you are out of the realm of electrostatics. The normal component of the electric field can be non-zero, because the conduction electrons are bound to the conductor. Of course, if you make the external electric field too strong you can free those electrons overcoming the binding energy, but then you also leave the realm of electrostatics, because again an electric current would flow.
Thank Tou very much for your answer ! That was i was thinking about.
 
Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'
So here is the motional EMF formula. Now I understand the standard Faraday paradox that an axis symmetric field source (like a speaker motor ring magnet) has a magnetic field that is frame invariant under rotation around axis of symmetry. The field is static whether you rotate the magnet or not. So far so good. What puzzles me is this , there is a term average magnetic flux or "azimuthal mean" , this term describes the average magnetic field through the area swept by the rotating Faraday...
Back
Top