Proving a Tangential Trig Identity

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SUMMARY

The discussion centers on proving the trigonometric identity tan^{-1}(\alpha) - tan^{-1}(\beta) = tan^{-1}\left(\frac{\alpha-\beta}{1+\alpha \beta}\right) using the Weierstrass substitution. Participants clarify that by setting α = tanX and β = tanY, the identity simplifies to tan(X - Y) = (tanX - tanY)/(1 + tanXtanY). This establishes a direct relationship between the inverse tangent function and the tangent subtraction formula.

PREREQUISITES
  • Understanding of inverse trigonometric functions
  • Familiarity with the tangent subtraction formula
  • Knowledge of the Weierstrass substitution technique
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the Weierstrass substitution in detail
  • Learn about the properties of inverse trigonometric functions
  • Explore proofs of trigonometric identities
  • Investigate applications of tangent subtraction in calculus
USEFUL FOR

Students studying trigonometry, mathematics educators, and anyone interested in proving trigonometric identities.

Char. Limit
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Homework Statement


I was reading on the Weierstrass substitution, and I came across the following trigonometric identity:

tan^{-1}(\alpha) - tan^{-1}(\beta) = tan^{-1}\left(\frac{\alpha-\beta}{1+\alpha \beta}\right)

Homework Equations



I'm not really sure which equations are applicable here.

The Attempt at a Solution



What my question is is "how is this proven?". And try as I might, I don't see a way to prove this. Any help would be deeply appreciated.
 
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Hi Char! :smile:

If α = tanX and β = tanY, it says tan(X - Y) = (tanX - tanY)/(1 + tanXtanY) :wink:
 
tiny-tim said:
Hi Char! :smile:

If α = tanX and β = tanY, it says tan(X - Y) = (tanX - tanY)/(1 + tanXtanY) :wink:

Hello tiny-tim!

Oh wow, it does. Thanks!
 

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