Taylor Classical Mechanics example 4.9

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SUMMARY

The discussion centers on the application of energy conservation in Taylor's Classical Mechanics, specifically regarding a uniform rigid cylinder rolling down a slope. Participants clarify that while static friction is present, it does not perform work in the context of energy conservation, as it transforms translational kinetic energy into rotational kinetic energy without dissipating energy as heat. The conversation also references Kleppner and Kolenkow's work to reinforce the understanding that gravity is the primary force doing work in this scenario, while static friction facilitates energy transformation.

PREREQUISITES
  • Understanding of energy conservation principles in physics
  • Familiarity with static friction and its role in mechanics
  • Knowledge of rotational kinetic energy concepts
  • Basic grasp of classical mechanics as presented in Taylor's Classical Mechanics
NEXT STEPS
  • Study Kleppner and Kolenkow's Chapter 7 on fixed axis rotation
  • Explore the concept of static friction and its work in various scenarios
  • Review energy conservation examples in classical mechanics
  • Analyze the role of gravity in mechanical systems
USEFUL FOR

Students of physics, educators teaching classical mechanics, and anyone interested in the principles of energy conservation and the dynamics of rolling motion.

almarpa
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Hello all.

I have almost finished chapter 4 on energy in Taylor's classical mechanics book. But in the last example in this chapter I got confused. Here it is:

"A uniform rigid cylinder of radius R rolls without slipping down a sloping track
as shown in Figure 4.23. Use energy conservation to find its speed v when it
reaches a vertical height h below its point of release."

In the solution, Taylor says that internal forces can be ignored, and that external forces are friction and normal forces of the track, and gravity. Now, here is what I do not understand: he claims that normal and friction force do no work! I see why normal force doesn't work, but, what about friction? Why doesn`t friction do any work?

Best regards all of you, and thank you for your help,
 
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But, if the cylinder is not sliding, should not we say that there is no friction force at all?
 
almarpa said:
But, if the cylinder is not sliding, should not we say that there is no friction force at all?

No, because there are forces other than friction acting on the cylinder that would make the cylinder slip if a static frictional force was not present. If the cylinder was rolling without resistance on a flat plane, then we could say that there was no static frictional force.
 
Now I see!

So the force we are talking about is static friction, which does no work as soon as the cylinder starts rolling, isn't it?
 
almarpa said:
the force we are talking about is static friction, which does no work

Right. I would be hard-pressed to find an example of a situation in which static friction does work.

Do you understand why the static frictional force in the problem does not do work?
 
AlephNumbers said:
I would be hard-pressed to find an example of a situation in which static friction does work.

That's exactly what I was thinking right now.

Now everything is clear to me.
Thank you so much form your help and your time.
 
Hello all again.

Now that I have studied Kleppner - Kolenkow chapter 7 on fixed axis rotation, I can answer my own question.

The friction forse is doing work, but, as the cylinder is not sliding, this work is employed in transforming part of the traslational kinetic energy in rotational kinetic energy, and not in dissipating mechanical energy as heat, so mechanical energy is conserved, altough friction is present (see Kelppner - Kolenkow, example 7.17).

I think this is the right answer.

What do you think?
 
almarpa said:
Hello all again.

Now that I have studied Kleppner - Kolenkow chapter 7 on fixed axis rotation, I can answer my own question.

The friction forse is doing work, but, as the cylinder is not sliding, this work is employed in transforming part of the traslational kinetic energy in rotational kinetic energy, and not in dissipating mechanical energy as heat, so mechanical energy is conserved, altough friction is present (see Kelppner - Kolenkow, example 7.17).

I think this is the right answer.

What do you think?

No, the friction is not doing the work. Gravity is doing the work and friction translates that work into rotational KE.

Another example is a particle sliding down a smooth curve. Gravity is doing all the work, but the normal force can translate vertical speed into horizontal speed (and vice versa).

The pendulum is another example.
 
Last edited:
  • #10
All right.

Thank you all for your replies.

Everything is clear now.
 
  • #11
AlephNumbers said:
Right. I would be hard-pressed to find an example of a situation in which static friction does work.

Do you understand why the static frictional force in the problem does not do work?

Static friction can do work. An example would be a box on the back of a truck. If the truck is accelerating, but the box does not slide relative to the truck, then the static frictional force on the box is doing positive work.
 
  • #12
Rolls With Slipping said:
Static friction can do work. An example would be a box on the back of a truck. If the truck is accelerating, but the box does not slide relative to the truck, then the static frictional force on the box is doing positive work.
This is a very old thread, but you are right to correct the misinformation here. As you say, static friction as an external force can do equal and opposite work on the two objects in contact.
As a reference, see last para at https://scripts.mit.edu/~srayyan/PERwiki/index.php?title=Static_friction
 

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