Taylor polynom of f(x)=1/(√1-e3x)

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1. May 29, 2016

Susenkovykral

• Member warned about posting homework/exam problems with no effort shown
Hello,

I can't find solution for Maclaurin (Taylor a=0) polynom of function: f(x)=1/(√1-e3x).

Thank you so much for help

Andrea

2. May 29, 2016

Staff: Mentor

I think something went wrong with formatting. I guess you didn't mean$$f(x) = \frac 1 {\sqrt 1 - e3x}$$
Is this homework?

3. May 29, 2016

Susenkovykral

I'm sorry. I made wrong formattion. The function is in the picture http://file:///C:/Users/nemkv/Desktop/function.JPG [Broken]

It is from the exams.

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Last edited by a moderator: May 7, 2017
4. May 29, 2016

Staff: Mentor

I moved the thread to the homework section.
$$f(x)=\sqrt{1-e^{3x}}$$
Where did you run into problems?

Edit: Fixed sign. With minus it is odd.

Last edited: May 29, 2016
5. May 29, 2016

Susenkovykral

6. May 29, 2016

Ray Vickson

The function $f(x) = \sqrt{1-e^{3x}}$ does not have a series expansion in powers of $x-a$ when $a = 0$ (that is, a Maclauren expansion). The function $f(x)$ is real when $x < 0$ but is pure imaginary when $x > 0$, and there is no way any function like that can have a Maclauren expansion.

This is either a "trick" question or else you copied it incorrectly.

Last edited by a moderator: May 29, 2016
7. May 29, 2016

Susenkovykral

Thank you so much. I have checked the function and I have copied it correctly. So It really looks like a trick.