Taylor Polynomial approximation

zjhok2004
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Homework Statement


obtain the number r = √15 -3 as an approximation to the nonzero root of the equation x^2 = sinx by using the cubic Taylor polynomial approximation to sinx

Homework Equations


cubic taylor polynomial of sinx = x- x^3/3!

The Attempt at a Solution


Sinx = x-x^3/3! + E(x)
x^2 = x-x^3/6+ E(x)How do I able to obtain the r?
 
Last edited:
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In order to get exact equality you need
$$\sin(x) = x - x^3/6 + E(x)$$
where ##E(x)## is the error due to using only two terms. As an approximation, we assume this error to be zero, so we pretend that
$$\sin(x) = x - x^3/6$$
and solve the equation
$$x^2 = x - x^3/6$$
 
jbunniii said:
In order to get exact equality you need
$$\sin(x) = x - x^3/6 + E(x)$$
where ##E(x)## is the error due to using only two terms. As an approximation, we assume this error to be zero, so we pretend that
$$\sin(x) = x - x^3/6$$
and solve the equation
$$x^2 = x - x^3/6$$
But how do I able to obtain the number r?
 
zjhok2004 said:
But how do I able to obtain the number r?
As the problem statement says, ##r## is a nonzero root of the equation ##x^2 = \sin(x)##. You will find an approximation to this by solving the equation ##x^2 = x - x^3/6##.
 
jbunniii said:
As the problem statement says, ##r## is a nonzero root of the equation ##x^2 = \sin(x)##. You will find an approximation to this by solving the equation ##x^2 = x - x^3/6##.
Solved, thanks!
 
Last edited:

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