Taylor Polynomial of Degree 2 in (0,a): Local Minima Analysis

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SUMMARY

The discussion focuses on the analysis of the Taylor polynomial of degree 2 for the function f(x, y) = sqrt(1 + 5x + 7y) at the point (0, 8). The user calculated the first partial derivatives, df/dx and df/dy, yielding values of 5/sqrt(57) and 7/sqrt(57), respectively. The conclusion drawn is that since the derivatives do not equal zero, the function does not have a local minimum at the specified point. The correctness of this approach was questioned, indicating a need for more detailed calculations.

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electricman
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Hi,

I want to confirm this:

a=8 , b=5 , c=7

Decide the Taylor polynomial of degree 2 in the point (0, a) to the function f (x, y)=sqrt(1+bx+cy). Decide with the aid of Taylor polynomial if the function has a local minimum in (0, a).

I used the partial derivates:

df/dx = 5/(2*sqrt(1+5x+7y)) = 5/sqrt(57)
df/dy = 7/(2*sqrt(1+5x+7y)) = 7/sqrt(57)
and so on with the rest of the derivates

And with the all derivates in the taylor polynomial i will get a value different then 0 and that mean that it haven't got a minimum.

Is this the correct way to slove this?
 
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electricman said:
Hi,

I want to confirm this:

a=8 , b=5 , c=7

Decide the Taylor polynomial of degree 2 in the point (0, a) to the function f (x, y)=sqrt(1+bx+cy). Decide with the aid of Taylor polynomial if the function has a local minimum in (0, a).

I used the partial derivates:

df/dx = 5/(2*sqrt(1+5x+7y)) = 5/sqrt(57)
df/dy = 7/(2*sqrt(1+5x+7y)) = 7/sqrt(57)
and so on with the rest of the derivates
Well, these should be 5/{2sqrt(57)} and 7/{2sqrt(57)}.

And with the all derivates in the taylor polynomial i will get a value different then 0 and that mean that it haven't got a minimum.

Is this the correct way to slove this?

I think you should show some more work-- I can't tell what you've done if I can't see it!
 

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