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## Main Question or Discussion Point

Hello folks,

I have this function, un complex numbers

[itex]\frac{1}{(1+z^2)}[/itex]

I know that the Taylor serie of that function is

[itex]\frac{1}{(1+z^2)}[/itex] = [itex]\sum (-1)^k.z^(2.k) [/itex]

I have this function, un complex numbers

[itex]\frac{1}{(1+z^2)}[/itex]

I know that the Taylor serie of that function is

[itex]\frac{1}{(1+z^2)}[/itex] = [itex]\sum (-1)^k.z^(2.k) [/itex]