MHB Taylor Series: Find 2nd Degree Series for x^2+y^2=4 at [1, -\sqrt[]{3}]

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To find the second-degree Taylor series for the equation x² + y² = 4 at the point [1, -√3], one must first identify the function and its derivatives at that point. The second-degree Taylor polynomial is structured as f(h) + f'(h)(x - h) + (f''(h)/2)(x - h)². Participants in the discussion emphasize the importance of evaluating the function and its first two derivatives at the point of interest. This evaluation is crucial for constructing the Taylor series accurately.
Anewk
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How would I find the second-degree Taylor series for $$x^2+y^2=4$$ at $$[1, -\sqrt[]{3}]$$?
 
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Hello and welcome to MHB! :D

Can you tell us what you've tried so we know where you are stuck or what you may be doing wrong? We can offer better help that way.
 
Anewk said:
How would I find the second-degree Taylor series for $$x^2+y^2=4$$ at $$[1, -\sqrt[]{3}]$$?

The second degree Taylor polynomial for a function $\displaystyle \begin{align*} f(x) \end{align*}$ centred at the point is $\displaystyle \begin{align*} (h, k) \end{align*}$ is $\displaystyle \begin{align*} f(x) = f(h) + f'(h) \, \left( x - h \right) + \frac{f''(h)}{2} \, \left( x - h \right) ^2 \end{align*}$.

Can you evaluate $\displaystyle \begin{align*} f(1), f'(1), f''(1) \end{align*}$?
 
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