Technicality of describing where sqrt(x) is increasing

  • Level: High School 
  • Thread starter Thread starter chadpip
  • Start date Start date
  • Tags Tags
    Increasing
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
2 replies · 4K views
chadpip
Messages
7
Reaction score
0
When describing where $sqrt{x}$ (square root of x) is increasing, it's from zero to infinity. But, do you say (0,inf) or [0, inf) ?

(I'm tutoring a student in pre-calc, and this came up. They don't know any calculus.)

In a situation like where is $x^2$ inc/dec, we'd say inc: (0, inf) and dec (-inf, 0). We wouldn't include the zero because that's the point where the function switches from dec to inc.

But on square root of x, it's not "switching" from dec to inc, so can we include that zero?

Thanks so much.
 
Physics news on Phys.org
A function f is monotonically increasing over some set S if for any [itex]x<y \Rightarrow f(x) < f(y) \, \forall x,y \in S[/itex]. No need for derivatives here! With this definition, you could say [tex]\sqrt x[/itex] is a monitonically increasing function over the set [itex]S=[0,\infty)[/itex].[/tex]
 
D H said:
A function f is monotonically increasing over some set S if for any [itex]x<y \Rightarrow f(x) < f(y) \, \forall x,y \in S[/itex]. No need for derivatives here! With this definition, you could say [tex]\sqrt x[/itex] is a monitonically increasing function over the set [itex]S=[0,\infty)[/itex].[/tex]
[tex] And also, note that [itex]x^2[/itex] is strictly increasing on [itex][0, +\infty)[/itex]![/tex]