Temperature and pressure problem

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In a closed container, pressure increases with temperature, which can be explained using the ideal gas law, PV = nRT. For a constant volume of 496.5 cubic inches, the relationship between pressure and temperature can be expressed as P/T = Constant. By rearranging the equation, the pressure at a higher temperature can be calculated using the formula P1/T1 = P2/T2. Given an initial temperature of 120°F and pressure of 6 psi, the pressure can be determined for a temperature increase to 900°F. Understanding these relationships is crucial for solving gas behavior problems in closed systems.
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I know that in a closed container, pressure increases as temperature increases, but I am having trouble trying to explain it mathematically. I did some searching around and came up with this formula: PV = nRT. I am having some trouble trying to apply this to my scenario;

closed volume - 496.5 cu-inche (~.5 L)
Temperature - 120* F
Pressure - 6 psi (~.41 bar)

The volume remains constant. What would the pressure be if the temperature increased to 900* F?
 
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All you need to do is rearrange the equation and drop out the constants. I'm not a big fan of derivations, but...

Since n, V, and R are constants...
P/T=Constant
P1/T1=P2/T2

There are many forms for the ideal gas equation...
 
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