Temperature and pressure problem

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SUMMARY

The discussion focuses on the relationship between temperature and pressure in a closed container, utilizing the ideal gas law represented by the formula PV = nRT. The user presents a scenario with a closed volume of 496.5 cubic inches, an initial temperature of 120°F, and a pressure of 6 psi. By applying the formula P1/T1 = P2/T2, the user seeks to determine the pressure at a temperature of 900°F, emphasizing the constants in the equation.

PREREQUISITES
  • Understanding of the ideal gas law (PV = nRT)
  • Knowledge of pressure and temperature units (psi, bar, Fahrenheit)
  • Basic algebra for rearranging equations
  • Familiarity with the concept of closed systems in thermodynamics
NEXT STEPS
  • Research the derivation of the ideal gas law and its applications
  • Learn how to convert between different pressure and temperature units
  • Explore real-world applications of the ideal gas law in engineering
  • Investigate the behavior of gases under varying conditions using simulations
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Students in physics or engineering, professionals in thermodynamics, and anyone interested in understanding gas behavior in closed systems.

abawp
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I know that in a closed container, pressure increases as temperature increases, but I am having trouble trying to explain it mathematically. I did some searching around and came up with this formula: PV = nRT. I am having some trouble trying to apply this to my scenario;

closed volume - 496.5 cu-inche (~.5 L)
Temperature - 120* F
Pressure - 6 psi (~.41 bar)

The volume remains constant. What would the pressure be if the temperature increased to 900* F?
 
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All you need to do is rearrange the equation and drop out the constants. I'm not a big fan of derivations, but...

Since n, V, and R are constants...
P/T=Constant
P1/T1=P2/T2

There are many forms for the ideal gas equation...
 

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