A crate of fruit with a mass of 33.5kg and a specific heat capacity of 3650 J/kg*K slides 8.20m down a ramp inclined at an angle of 37.6 degrees below the horizontal.
If an amount of heat equal to the magnitude of the work done by friction is absorbed by the crate of fruit and the fruit reaches a uniform final temperature, what is its temperature change ?
Change in temperature = gLsin(theta)/c - v^2/2c
The Attempt at a Solution
I am doing the following equation above and I am getting an answer of -3.00 * 10^-3 and it keeps saying it is wrong. I am not sure what I am doing wrong. I have it set up like this:
9.81*8.2*sin(37.6)/3650 - (2.4)^2/(2)(3650)
Any help would be appreciated, thanks!