Temperature of Pluto's Atmosphere

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SUMMARY

The discussion centers on estimating the temperature of Pluto's atmosphere based on observations from 1988, which indicated that the atmospheric density at 50 km is one-third of that at the surface. The atmosphere is primarily composed of nitrogen (N2). Key parameters include Pluto's mass of approximately 1.5x1022 kg and a radius of about 1200 km. The approach involves equating gravitational energy with temperature to determine an upper limit on the atmospheric temperature.

PREREQUISITES
  • Understanding of gravitational energy and escape velocity concepts
  • Familiarity with diatomic molecular energy equations
  • Knowledge of atmospheric density and its implications
  • Basic principles of thermodynamics related to temperature estimation
NEXT STEPS
  • Research the relationship between gravitational energy and temperature in planetary atmospheres
  • Study the properties of nitrogen (N2) as a diatomic molecule
  • Learn about the methods of estimating atmospheric density and its effects on temperature
  • Explore the concept of escape velocity and its relevance to atmospheric retention
USEFUL FOR

Astronomers, astrophysicists, and students studying planetary atmospheres or thermodynamics will benefit from this discussion.

viviolet
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Homework Statement


In 1988 telescopes viewed Pluto as it crossed in front of a distant star. As the star emerged from behind the planet, light from the star was slightly dimmed as it went through Pluto’s atmosphere. The observations indicated that the atmospheric density at a height of 50 km above the surface of Pluto is about one-third the density at the surface. The mass of Pluto is known to be about 1.5x10^22 kg, and its radius is about 1200 km. Spectroscopic data indicate that the atmosphere is mostly nitrogen (N2). Estimate the temperature of Pluto’s atmosphere. State what approximations and/or simplifying assumptions you made.

Homework Equations


C= deltaEatom/detlaT
Average energy of a diatomic molecule = translational energy + vibrational energy + rotational energy + gravitational energy
= 1.2mvx^2 + 1/2 mvy^2 + 1/2mvz^2 + (1+ m1/m2)(p1^2/2m1) + 1/2kS^2 + L^2rotx/2I + L^2roty/2I + Mgycm/
...?

The Attempt at a Solution


I don't think I even understand how to approach this - there is no change in energy given. None of the equations I have seem to explain how to figure out something's temperature based only on its size... The only think I can think of is trying to equate gravitational energy and temperature somehow.
 
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For the atmosphere to stay attached the molecular speed has to be less than escape velocity. That gives you an upper limit on the temperature.
 

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