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Engineering
Mechanical Engineering
Tensile Test of Slip Ring - Working out Tensile Strength
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[QUOTE="Delvaurius, post: 6033098, member: 648967"] All, Through work, I've recently been tasked with investigating a very old tensile test technique, according to BS HC 403:1977 (now withdrawn). Essentially, you take a ring. Anywhere along it you make a slit all the way through. You then pull that ring in a tensile machine, ensuring that the slit is perpendicular to the direction of force. The standard then states, to work out the tensile strength, use the equation: S = (3*P*((D/t)-1)) / b*t S = Stress, P = Load, D = Outer Diameter, t = radial thickness, b = width. Now I get the whole thing over (b*t) where b*t is the cross sectional area of the ring, meeting S=F/A. How is Force = 3P((D/t) - 1) derived? Thanks for any help! [/QUOTE]
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Forums
Engineering
Mechanical Engineering
Tensile Test of Slip Ring - Working out Tensile Strength
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