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Tension at at the bottom of the pendulum

  1. Mar 23, 2016 #1
    1. The problem statement, all variables and given/known data
    A ball of mass m is attached to a string of length L and released from rest at point A. Show that the tension in the string when the ball reaches point B is 3mg, independent of the length l. (there is an image in attachment )


    2. Relevant equations
    K = mv2/2
    U = mgh
    Fcp = mv2/r

    3. The attempt at a solution
    The mechanical energy at point A must equal the mechanical energy at point B. h is the vertical distance between A and B.
    So mv2/2 - mgh = 0 and v2 = 2gh
    The net force acting on the ball at point B is the centripetal force, which is mv2/L and is equal with T - mg.
    mv2/L = T - mg.
    So T = mv2/L + mg.
    T = 2mgh/L + mg
    θ is the angle between the string and the vertical when the ball is at point A.
    If I write h = L - Lcosθ I get to the equation T = mg(2 - 2cosθ + 1), which is 3mg only when θ is 90°. Something must be wrong.
     

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    Last edited: Mar 23, 2016
  2. jcsd
  3. Mar 23, 2016 #2
    i think the total energy at A is transferred to the bob as kinetic energy -therefore
    yourwork out is correct.
    Is there a problem if theta is 90 degree?
     
  4. Mar 23, 2016 #3
    I think the problem wants to show that T = 3mg no matter at what angle the ball begins to move.

    L.E: thinking about what drvrm said, I guess it is not possible that T is independent of θ. So, is the problem text wrong? (l is the horizontal line between point A and the string when the ball is in point B)
     
    Last edited: Mar 23, 2016
  5. Mar 23, 2016 #4

    haruspex

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    There's nothing (well, not much) wrong with the question, but you may be misinterpreting it. Ignore the angle theta. You are only interested in the motion from A to B. The string is depicted in a later position, at angle theta past B, just to make the physical set-up clearer.

    The one thing that is not clear is that it asks for the tension "when the ball reaches point B". The tension exactly at B is indeterminate, for the simple reason that it transitions at that point from an arc of radius l to an arc of radius L. For the question to make sense, you have to read it as "as the ball reaches point B", i.e. immediately before B.
     
  6. Mar 23, 2016 #5
    The ball is suspended from a string tied to the roof. There's only one string, so only one radius, L. l is the horizontal distance between point A and the radius in point B. Or so I interpret the image + the problem text. Unfortunately, the image is blurry.
     
    Last edited: Mar 23, 2016
  7. Mar 23, 2016 #6

    haruspex

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    That's not how I read the diagram. There is a black spot above B and to the right of A, which appears to represent some kind of peg. The dotted line showing the trajectory clearly describes an arc centred on the peg as it goes from A to B. Moreover, my interpretation leads to the expected answer.
     
  8. Mar 23, 2016 #7
    Assuming that the ball is suspended from the little black peg, the angle it makes in point A with the vertical is 90°. So applying my calculations, the tension in point B would be 3mg, just as specified in the problem text. But, once it arrives in point B, how could it change the radius while still being suspended from that black peg? It could, if there were 2 strings: L beginning in the roof and l beginning in the black peg. But the problem would become quite complicated in this interpretation, and quite distant from the text provided (it's from walker textbook, energy conservation chapter). I think there's a problem with the problem text and diagram.
     
  9. Mar 23, 2016 #8

    haruspex

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    It is not, according to the diagram, suspended from the peg. It is suspended from a point L-l above the peg. But the peg interferes with the string while the mass is left of the vertical position.
    I agree that it seems pointless to have such an elaborate set-up. The problem as stated would have worked just as well suspending it from the peg. Are there more parts to the question?
     
  10. Mar 24, 2016 #9
    Point b of the problem text: "Give a detailed physical explanation for the fact that the tension at the point B is independent of length l."

    It can't be suspended above the peg if it is to hang (at least initially) from a string of length l. (that's what I understand if it is to change radius to L at point B).
    Anyway, I don't think we should waste our time doing diagram hermeneutics.
     
    Last edited: Mar 24, 2016
  11. Mar 24, 2016 #10

    haruspex

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    Not sure what you are saying there, but here is my interpretation of the diagram. The string is length L, and attached to some point, call it O. The string hangs vertically from there to a peg at point P, then is pulled under and around the peg to go horizontally to point A. The length of PA is lowercase l.
    When released, the mass will swing in an arc of radius l until it is vertically below P, then will continue in an arc of radius L.
    That is entirely consistent with the text, with the diagram, and with the result to be proved (provided we read 'reaches B' as immediately before reaching B).
     
  12. Mar 24, 2016 #11
    You are right, this explanation is consistent with all the problem data. But besides knowing some physics, one has to be a bit of Sherlock Holmes to solve it... :smile:
     
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