Tension of a string attached to an instrument inside rocket

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The discussion revolves around calculating the tension in a wire holding a 6.00-kg instrument inside a rocket landing vertically while decelerating at 2.40 m/s². Participants clarify the forces acting on the instrument, which include gravity and the tension from the wire, emphasizing the importance of distinguishing between forces and accelerations. The gravitational force is calculated as 58.8 N (6 kg * 9.8 m/s²), and the net force equation is established as T - mg = ma. After some confusion, the correct approach is confirmed, leading to the successful calculation of tension in the wire. The conversation highlights the learning process and the importance of understanding the underlying physics concepts.
  • #31
physicsquestion said:
So the total force exerted on the instrument is T, and then mg, the force of gravity. ΣF=T+mg
Good. Now fill in the other side of the ΣF=ma equation.
 
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  • #32
Wait...

I got it

So I put T-mg=ma, or T-(6)(9.8)=(6)(2.4) and then I got my answer.

Yay ^^
 
  • #33
physicsquestion said:
Wait...

I got it

So I put T-mg=ma, or T-(6)(9.8)=(6)(2.4) and then I got my answer.

Yay ^^
Good. It is now also well with your algebra.
 

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