Tension of an Object Swinging in a Circle

  • Thread starter Thread starter wallace13
  • Start date Start date
  • Tags Tags
    Circle Tension
Click For Summary
SUMMARY

The discussion focuses on calculating the speed and tension of a swing ride chair with a 10 m radius and a mass of 210 kg. The speed was correctly determined to be 12.175 m/s using the equation tan θ = m × v² / g. However, the initial calculation for tension in the cable, resulting in 3112 N, was incorrect. Participants emphasized the importance of considering the components of cable tension and recommended using a free body diagram to illustrate the forces acting on the chair.

PREREQUISITES
  • Understanding of centripetal force and its calculation
  • Familiarity with trigonometric functions in physics
  • Knowledge of free body diagrams and force components
  • Basic principles of rotational motion
NEXT STEPS
  • Study the derivation of centripetal force equations in circular motion
  • Learn how to construct and analyze free body diagrams
  • Explore the relationship between tension and angle in inclined systems
  • Investigate the effects of mass and radius on rotational speed
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in understanding the dynamics of circular motion and tension in rotating systems.

wallace13
Messages
31
Reaction score
0
A "swing" ride at a carnival consists of chairs that are swung in a circle with a 10 m radius. It is attached to a vertical rotating pole with a 56.5 degree angle between the pole and chain of a swing. Suppose the total mass of a chair and its occupant is 210 kg.

(a) Determine the speed of the chair.
I found the speed of the chair by using the equation tan 0 = m x v squared/gr
I got 12.175m/s and it is correct.

(b) Determine the tension in the cable attached to the chair.
I plugged the velocity that I found into the equation Fc= m x v squared/r
I got 3112 N, which is incorrect



tan 0= m x v squared/gr
Ac= v squared/r
Tc= mxac
 
Physics news on Phys.org
wallace13 said:
(b) Determine the tension in the cable attached to the chair.
I plugged the velocity that I found into the equation Fc= m x v squared/r
That will give you the centripetal force, not the tension in the cable. Hint: Consider the components of the cable tension. (You would be wise to draw a free body diagram illustrating the forces acting on the chair.)
 

Similar threads

Replies
8
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
10K
  • · Replies 26 ·
Replies
26
Views
4K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
8K