Tension Problem: Two boxes with two ropes

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SUMMARY

The discussion centers on calculating the tensions in a system involving two masses, Ma and Mb, connected by a heavy rope with mass Mr, while the top mass Ma is suspended from a massless rope attached to a helicopter accelerating upwards at acceleration a. The derived equations for tension are T1 = (Ma + Mb + Mr) * (a + g) for the top rope, T2.1 = (Mb + Mr) * (a + g) for the heavy rope pulling downward on Ma, and T2.2 = Mb * (a + g) for the tension pulling upward on Mb. The solution is validated by checking the limiting case where the mass of the rope approaches zero, confirming the results align with those of a massless rope.

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awelex
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Hi,
here's a problem I did earlier today. I think I got it right, but I'd appreciate it if somebody could check. Also, is there a different way to solve this problem?


Homework Statement


Two masses Ma and Mb are connected through a heavy rope with mass Mr. The top mass Ma is hanging from a from a massless rope that is that is attached to a helicopter that moves upwards with acceleration a. Find the tension in the top rope as well as the tensions in the bottom (heavy) rope.

I labeled the tension of the top rope T1, the tension of the heavy rope pulling downward on Ma T2.1, and the tension pulling upward on Mb T2.2.


Homework Equations


For mass A: Fnet = Ma * a
--> T1 - T2.1 - Ma * g = Ma * a
--> T1 - T2.1 = Ma * a + Ma * g

For mass B: Fnet = Mb * a
--> T2.2 - Mb * g = Mb * a
--> T2.2 = Mb * a + Mb * g
This already gives us the tension from the heavy rope pulling upwards on the second mass.

For the entire system, without the top rope:
Fnet = (Ma + Mb + Mr) * a
--> T1 - (Ma + Mb + Mr) * g = (Ma + Mb + Mr) * a
--> T1 = (Ma + Mb + Mr) * (a + g)

I plugged this into the earlier equation with T1 and T2.1:

(Ma + Mb + Mr) * (a + g) - T2.1 = Ma * (a + g)
--> T2.1 = (Mb + Mr) * (a + g)

So we have:
T1 = (Ma + Mb + mr) * (a + g)
T2.1 = (Mb + Mr) * (a + g)
T2.2 = Mb * (a + g)

The Attempt at a Solution



See above.

Is this correct?
 
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That looks good.
You can check your answer in limiting case. When mass of the rope goes to zero, your answer gives the same result as massless rope.
 
Cool, thanks.
 

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