Tensor of electromagnetic field

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The electromagnetic field tensor is defined as F_{\mu\nu}=\frac{\partial A_{\nu}}{\partial x^{\mu}}-\frac{\partial A_{\mu}}{\partial x^{\nu}}, which captures the relationship between electric and magnetic fields. The tensor is antisymmetric, meaning F_{\mu\nu}=-F_{\nu\mu}, and its diagonal components are zero, indicating that there are no self-interactions in the fields. The discussion raises questions about the choice of this specific formulation over alternatives, but it is emphasized that the tensor nature is essential for transforming electric and magnetic fields across different reference frames. Understanding the historical context and reasoning behind this definition is important for grasping its significance in electromagnetism. The formulation of F_{\mu\nu} is foundational in describing electromagnetic phenomena.
Petar Mali
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F_{\mu\nu}=\frac{\partial A_{\nu}}{\partial x^{\mu}}-\frac{\partial A_{\mu}}{\partial x^{\nu}}

F_{\mu\nu}=-F_{\nu\mu}

F_{ii}\equiv 0

F_{11}=F_{22}=F_{33}=F_{44}=0
where

A_{\mu}=(-\vec{A},\frac{1}{c}\varphi)(F_{\mu\nu})=\left(\begin{array}{cccc}<br /> 0&amp; -B_z&amp;B_y&amp; -\frac{1}{c}E_x\\<br /> B_z&amp;0&amp;-B_x&amp; -\frac{1}{c}E_y \\<br /> -B_y&amp;B_x&amp;0&amp;-\frac{1}{c}E_z\\<br /> \frac{1}{c}E_x&amp; \frac{1}{c}E_y &amp; \frac{1}{c}E_z &amp; 0\\<br /> \end{array} \right)F^{\mu\nu}=g^{\mu\rho}g^{\nu\sigma}F_{\rho\sigma}(F^{\mu\nu})=\left(\begin{array}{cccc}<br /> 0&amp; -B_z&amp;B_y&amp; \frac{1}{c}E_x\\<br /> B_z&amp;0&amp;-B_x&amp; \frac{1}{c}E_y \\<br /> -B_y&amp;B_x&amp;0&amp;\frac{1}{c}E_z\\<br /> -\frac{1}{c}E_x&amp; -\frac{1}{c}E_y &amp; -\frac{1}{c}E_z &amp; 0\\<br /> \end{array} \right)

How do I know that rotA_{\mu}=\frac{\partial A_{\nu}}{\partial x^{\mu}}-\frac{\partial A_{\mu}}{\partial x^{\nu}} is electromagnetic field tensor?
 
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Hi Petar! :smile:
Petar Mali said:
How do I know that rotA_{\mu}=\frac{\partial A_{\nu}}{\partial x^{\mu}}-\frac{\partial A_{\mu}}{\partial x^{\nu}} is electromagnetic field tensor?

I don't understand your question :redface:

isn't Aµ defined as the potential of the electromagnetic field tensor (in which case that has to be rotA)?
 
Well its all ok for me except why I say that <br /> F_{\mu\nu}=\frac{\partial A_{\nu}}{\partial x^{\mu}}-\frac{\partial A_{\mu}}{\partial x^{\nu}}<br />

is EM field tensor. Why not

<br /> F_{\mu\nu}=\frac{\partial A_{\mu}}{\partial x^{\nu}}-\frac{\partial A_{\nu}}{\partial x^{\mu}}<br />

for example?

Or some other functions?

It's like a postulate. EM field tensor is <br /> F_{\mu\nu}=\frac{\partial A_{\nu}}{\partial x^{\mu}}-\frac{\partial A_{\mu}}{\partial x^{\nu}}<br />

Let's form a matrix. No problem. Components of that matrix are electric field components and magnetic field components. Ok. That have sence. But how I know to start with F_{\mu\nu}. Do you know perhaps history of this problem.
 
Petar Mali said:
Why not

<br /> F_{\mu\nu}=\frac{\partial A_{\mu}}{\partial x^{\nu}}-\frac{\partial A_{\nu}}{\partial x^{\mu}}<br />

for example?

That's minus the electromagnetic field tensor, so yes, it'll also be an electromagnetic field tensor.
Let's form a matrix. No problem. Components of that matrix are electric field components and magnetic field components. Ok. That have sence. But how I know to start with F_{\mu\nu}. Do you know perhaps history of this problem.

As you say, E and B are the 6 components of F.

F has to be a tensor because experiment tells us that is the way E and B transform in different frames. :smile:
 

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