Terminal Velocity: Student Investigation & Incorrect Book Answer

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Barclay
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This is not a homework question. It is basic physics.

The question in the book relates to terminal velocity. I think the answer in the book is incorrect. Please advise.

Students are investigating how the area of a parachute affects the forces acting on it in freefall. Steel balls are attached to parachutes of varying sizes and then dropped from a fixed height, timing how long it takes to hit the ground.

Then the book asks a question:

Question: will the ball with the largest parachute will be traveling more quickly or more slowly than other balls traveling at terminal velocity?

I think the answer should be slowly but the book says quickly.

If you are the steel ball, wouldn't you rather have a large surface area parachute so that you fall slowly?
 
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I agree with you. It is difficult to second-guess the book without better context.

Given identical steel balls and different parachutes, the ball/parachute pair with the larger parachute should have the slower terminal velocity.

The ball with the larger parachute will reach (or approach) its terminal velocity in less elapsed time. But the wording of the question seems to make this fact irrelevant.
 
The balls are all the same size and mass. Only the parachute is changed
 
I have fallen at Terminal Velocity many times and I always found that a parachute slowed me down, On the 1 occasion that I used a smaller parachute I believe that I fell faster than with the larger parachute and a lot slower than without the parachute. I would always prefer to hit the ground with an open parachute than without a parachute. Text books do not always have correct answers and/or information. Nothing beats doing your own experiment. (Typos edited)
 
I have re read the question as posted "Question: will the ball with the largest parachute will be traveling more quickly or more slowly than other balls traveling at terminal velocity? " and I realize that I don't understand the question. Perhaps it has not been types correctly.