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Test for coplanarity of four points

  1. Oct 21, 2012 #1
    Hi all,
    If a,b,c,d are position vectors of four points A,B,C,D.The points will be coplanar if xa+yb+zc+td=0,x+y+z+t=0,provided x,y,z,t are not all 0,and they are scalars.Is this test needed to show 4 points are coplanar?
    If we consider two lines joining A,B and C,D then this will give us two vectors which are always coplanar.So points A,B,C,D are also coplanar.So I assumed that any 4 points are coplanar and no test is needed for it.
    Or is this the test to verify coplanarity of D with the plane containing A,B,C ?
    I'm wondering if my assumption is true?Please help me clarifying it.
    I'm new here ,Please treat my mistakes with forgiveness. :smile:
    Thanks.
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Oct 21, 2012 #2

    LCKurtz

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    What if A,B,C,D are the vertices of a regular tetrahedron?
     
  4. Oct 21, 2012 #3
    :smile:Thanks a lot for your clue.I think I'm getting near to it.Can you please take a look on the attachment....
    And please mention if I need some more things to do.
     

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  5. Oct 21, 2012 #4

    LCKurtz

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    My point was that your statement that any 4 points are coplanar is false. Remember that it takes three non-collinear points to determine a plane (their triangle is part of the plane). Four points are coplanar only if the 4th point lies in the plane determined by the first three.

    The test I would use for co-plane-ness of points A,B,C,D would be to make vectors of the sides like this: u = AB, v = AC, w = AD and calculate the triple scalar product or "box" product ##u\cdot v \times w##. If that is non-zero they aren't coplanar and if it is zero they are.
     
  6. Oct 22, 2012 #5
    Thanks a lot for your help.I think I got your point " Four points are coplanar only if the 4th point lies in the plane determined by the first three."
    Have a nice day!!!!!!:smile:
     
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