Find the relation between x,y and z

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The discussion focuses on finding the relationship between the variables x, y, and z in the context of coplanar points A, B, C, and D defined by their coordinates. The equation derived from the linear combination of these points is a(2-x, 2, 2) + b(2, 2-y, 2) + c(2, 2, 2-z) = (1, 1, 1). The conclusion drawn is that the relationship 1/x + 1/y + 1/z = 1 holds true under the condition that the vectors are not collinear, which introduces an additional constraint on the coefficients a, b, and c.

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Homework Statement


The coplanar points A,B,C,D are (2-x, 2,2); (2,2-y,2); (2,2,2-z): (1,1,1)

Homework Equations



The Attempt at a Solution


a(2-x, 2,2) + b(2,2-y,2) + c(2,2,2-z) = (1,1,1)

Equating respective components

ax=by=cz=k

The answer is 1/x + 1/y + 1/z = 1 but in my case it does not satisfy this.
 
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utkarshakash said:

Homework Statement


The coplanar points A,B,C,D are (2-x, 2,2); (2,2-y,2); (2,2,2-z): (1,1,1)

Homework Equations



The Attempt at a Solution


a(2-x, 2,2) + b(2,2-y,2) + c(2,2,2-z) = (1,1,1)

Equating respective components

ax=by=cz=k

The answer is 1/x + 1/y + 1/z = 1 but in my case it does not satisfy this.

Look here: http://mathworld.wolfram.com/Coplanar.html
 
utkarshakash said:
a(2-x, 2,2) + b(2,2-y,2) + c(2,2,2-z) = (1,1,1)
True, but there is another constraint on a, b, c. If the three vectors on the left are not collinear then with arbitrary a, b and c you could generate any vector in the space, not just those in the desired plane.
If you bring in that extra constraint, the result does follow.
 

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