Two coplanar lines and finding the equation

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SUMMARY

The discussion focuses on finding the equation of line b, which is perpendicular to line a, defined by the points (3,2,3) and (8,10,6). The user utilized the cross product to determine one direction vector and established the position vector at (3,2,3). To fully solve the problem, the user needs to find a second direction vector that incorporates the point (7,49,25) and understand the relationship between the vectors in the coplanar context.

PREREQUISITES
  • Understanding of vector mathematics, specifically direction vectors and position vectors.
  • Knowledge of the cross product and its application in finding perpendicular vectors.
  • Familiarity with the equation of a line in vector form: r = [x,y,z] + s [x1,y1,z1] + t [x2,y2,z2].
  • Basic concepts of coplanarity and the properties of planes in three-dimensional space.
NEXT STEPS
  • Learn how to apply the cross product to find direction vectors in three-dimensional space.
  • Study the properties of coplanar vectors and how to determine a plane's normal vector.
  • Explore methods for deriving the equation of a line given a point and direction vector.
  • Investigate the relationship between perpendicular lines and their respective direction vectors.
USEFUL FOR

Students studying vector mathematics, particularly those tackling problems involving coplanar lines and their equations, as well as educators looking for examples of vector applications in three-dimensional geometry.

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Homework Statement


Two coplanar lines, a and b are perpendicular to each other. a passes through the points (3,2,3) and (8,10,6). Find the equation for b if it passes through the point (7,49,25).


Homework Equations


The equation were trying to find is r = [x,y,z] + s [x1,y1,z1] + t [x2,y2,z2]



The Attempt at a Solution


Basically since the coordinates are perpendicular I used the cross product to find one direction vector. For my position vector I used (3,2,3). Now I'm not sure what to do with the last point (7,49,25) or what to do to find my second direction vector. I'm not even sure if I did the first part right. Help would be appreciated thanks!
 
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gundamshadow said:

Homework Statement


Two coplanar lines, a and b are perpendicular to each other. a passes through the points (3,2,3) and (8,10,6). Find the equation for b if it passes through the point (7,49,25).


Homework Equations


The equation were trying to find is r = [x,y,z] + s [x1,y1,z1] + t [x2,y2,z2]



The Attempt at a Solution


Basically since the coordinates are perpendicular I used the cross product to find one direction vector. For my position vector I used (3,2,3). Now I'm not sure what to do with the last point (7,49,25) or what to do to find my second direction vector. I'm not even sure if I did the first part right. Help would be appreciated thanks!

Hi gundamshadow, Welcome to PF.

Your question, being mathematical in nature, would probably fair better in the Precalculus forum. But I can give you a hint or two here :smile:

The lines involved are said to be coplanar, and that plane must have a normal. A plane's normal has some nice properties involving vectors in the plane and cross and dot products. You might want to look into that :wink:

You might start by finding any two vectors in the plane from the given points...
 

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