Two coplanar lines and finding the equation

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Homework Statement


Two coplanar lines, a and b are perpendicular to each other. a passes through the points (3,2,3) and (8,10,6). Find the equation for b if it passes through the point (7,49,25).


Homework Equations


The equation were trying to find is r = [x,y,z] + s [x1,y1,z1] + t [x2,y2,z2]



The Attempt at a Solution


Basically since the coordinates are perpendicular I used the cross product to find one direction vector. For my position vector I used (3,2,3). Now I'm not sure what to do with the last point (7,49,25) or what to do to find my second direction vector. I'm not even sure if I did the first part right. Help would be appreciated thanks!
 
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gundamshadow said:

Homework Statement


Two coplanar lines, a and b are perpendicular to each other. a passes through the points (3,2,3) and (8,10,6). Find the equation for b if it passes through the point (7,49,25).


Homework Equations


The equation were trying to find is r = [x,y,z] + s [x1,y1,z1] + t [x2,y2,z2]



The Attempt at a Solution


Basically since the coordinates are perpendicular I used the cross product to find one direction vector. For my position vector I used (3,2,3). Now I'm not sure what to do with the last point (7,49,25) or what to do to find my second direction vector. I'm not even sure if I did the first part right. Help would be appreciated thanks!

Hi gundamshadow, Welcome to PF.

Your question, being mathematical in nature, would probably fair better in the Precalculus forum. But I can give you a hint or two here :smile:

The lines involved are said to be coplanar, and that plane must have a normal. A plane's normal has some nice properties involving vectors in the plane and cross and dot products. You might want to look into that :wink:

You might start by finding any two vectors in the plane from the given points...
 

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