Test tomorrow, don't know how to do this simple question

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SUMMARY

The function f(x,y) = e^(-x-y) is uniformly continuous for x > 0 and y > 0. This conclusion is derived from the properties of the exponential function and the bounded nature of f within the interval [0, 1]. By introducing the variable r = x + y, where r > 0, one can effectively analyze the behavior of f and apply the epsilon-delta definition of uniform continuity. The boundedness of f ensures that for any chosen epsilon, a corresponding delta can be determined, confirming uniform continuity.

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  • Understanding of uniform continuity and its definition
  • Familiarity with the epsilon-delta method in calculus
  • Knowledge of the properties of the exponential function
  • Basic concepts of multivariable calculus
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  • Study the epsilon-delta definition of uniform continuity in detail
  • Explore the properties of the exponential function, particularly in multivariable contexts
  • Learn about the implications of bounded functions in uniform continuity
  • Investigate examples of uniform continuity in different mathematical functions
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Students and educators in calculus, mathematicians focusing on analysis, and anyone interested in understanding the principles of uniform continuity in multivariable functions.

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show that f(x,y) = e^(-x-y) is uniformly continuous if x>0 and y>0.

I duno how to start, I know the definition, but if I'm trying to do it the epsilon delta way i don't know how to pick delta and epsilon.
 
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how about noticing that f only varies between zero and 1...

also consider the variable r = x+y, with r>0
 

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