Testing Convergence of Series: \Sigma^{\infty}_{n=1}\left[1/3^{ln\:n}}\right]

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SUMMARY

The discussion focuses on testing the convergence of the series \(\Sigma^{\infty}_{n=1}\left[\frac{1}{3^{\ln n}}\right]\). The user expresses difficulty in selecting an appropriate convergence test, noting that many methods fail. A key insight provided is the transformation of \(3^{\ln{n}}\) into \(n^{\frac{1}{{\log_{3}{e}}}}\), which aids in understanding the series' behavior. This transformation is crucial for applying convergence tests effectively.

PREREQUISITES
  • Understanding of series convergence tests (e.g., Ratio Test, Root Test)
  • Familiarity with logarithmic properties and transformations
  • Basic knowledge of limits and asymptotic behavior
  • Experience with mathematical notation and series summation
NEXT STEPS
  • Research the Ratio Test and its application to series convergence
  • Explore the Root Test and how it can be applied to the given series
  • Study logarithmic transformations and their impact on series analysis
  • Investigate the concept of asymptotic equivalence in series
USEFUL FOR

Mathematicians, students studying calculus or real analysis, and anyone interested in series convergence and mathematical transformations.

hobbes33
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[tex]\Sigma[/tex][tex]^{\infty}_{n=1}[/tex][tex]\left[1/3^{ln\:n}}\right][/tex]

How do I go about testing the convergence of this series?

I have no clue which method I should be using, since most tests fails on this one.

You don't have to show me everything, just a nudge in the right direction should get me going on this question :)
 
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Might help to know that [tex]3^{\ln{n}}=3^{\frac{\log_{3}{n}}{\log_{3}{e}}}=n^\frac{1}{{\log_{3}{e}}}[/tex]
 
zcd said:
Might help to know that [tex]3^{\ln{n}}=3^{\frac{\log_{3}{n}}{\log_{3}{e}}}=n^\frac{1}{{\log_{3}{e}}}[/tex]

Ah, here's the critical link. I got it, thanks! :D
 

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