Testing the Impact of Different Prototypes: Dropping 20lbs from 10’

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Discussion Overview

The discussion centers around testing the impact of different prototypes by dropping a consistent weight (20lbs) from a consistent height (10 feet) to evaluate the resulting impact velocity and damage. The context involves experimental design and calculations related to physics principles, particularly focusing on the effects of gravity and air resistance.

Discussion Character

  • Experimental/applied
  • Mathematical reasoning
  • Conceptual clarification

Main Points Raised

  • One participant seeks to determine the impact velocity of a 20lbs weight dropped from 10 feet, asking for a simple formula to calculate this.
  • Another participant provides a formula for calculating impact velocity, v = √(2ad), where 'a' is the acceleration due to gravity and 'd' is the height dropped.
  • A later reply clarifies that the weight will be dropped onto a stationary product, not dropped from it, and requests a simplified explanation of the calculation using specific variables.
  • One participant suggests that for heavy weights, air resistance is negligible, indicating that height is the primary factor affecting impact velocity.
  • The same participant provides a specific calculation for the impact velocity at 10 feet, yielding a result of approximately 25.36 feet per second.

Areas of Agreement / Disagreement

Participants generally agree on the formula for calculating impact velocity and the negligible effect of air resistance for heavy weights. However, there is no consensus on the best way to explain the calculations, as one participant expresses difficulty with the mathematical concepts.

Contextual Notes

The discussion includes assumptions about the conditions of the drop, such as the weight being heavy enough for air resistance to be negligible. There are also unresolved aspects regarding the clarity of mathematical explanations and the implications of changing variables.

Who May Find This Useful

This discussion may be useful for individuals interested in experimental physics, product testing, or those seeking to understand the principles of impact dynamics and velocity calculations.

bp1945
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I am developing a new product. I am currently constructing various prototypes of the product changing only one component using a different material with each model.

I want to test the impact results of each different model dropping a consistent weight (i.e. 20lbs) from a consistent height (i.e. 10’) for each test so video these results to determine which model will best suit my needs.

So, this sounds like a simple question, dropping 20lbs from 20’, what will be the velocity at impact? And is there a simple formula I can use if I change the variables?
 
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bp1945 said:
I am developing a new product. I am currently constructing various prototypes of the product changing only one component using a different material with each model.

I want to test the impact results of each different model dropping a consistent weight (i.e. 20lbs) from a consistent height (i.e. 10’) for each test so video these results to determine which model will best suit my needs.

So, this sounds like a simple question, dropping 20lbs from 20’, what will be the velocity at impact? And is there a simple formula I can use if I change the variables?
If the products that you are dropping are relatively aerodynamic you can use a very simple formula:
v=\sqrt{2ad},
where
v is the velocity when the object hits the ground (ft/s)
a is the acceleration due to gravity (32.17 ft/s2)
d is the height you dropped it from (ft).
 
Hey gamesguru, thanks for your response. After reading your response and re-reading my question I realize I didn't make it quit clear.

I'm not dropping the product, the product will be stationary and parallel to the ground and I will be dropping the weight from a certain height straight down on the product to determine velocity and record (video) impact damage.

And gamesguru, I am worse than terrible at math so that formula scared the hell out of me. Can you do an example using 20lbs as the weight and 10ft. as the distance dropped. What I need to know is the velosity at impact using those two variables. And I may change variables to get different results.

Can you explain this to me in idiot terms?
 
As long as you work with fairly heavy weights, the role of air resistance will be negligible and so the weight will not matter, only the height will determine the impact velocity.
If you use my above formula, you will find (in feet):
velocity=\sqrt{64.34*height}.
You can use google now. To find the impact velocity at 10 feet just type "sqrt(64.34*10)" (without quotes) into google, hit enter. You will get 25.36. This means your weight will hit the product at a speed of 25.36 feet per second.
Hope that helps.
 
Thanks gamesguru, this helps greatly.
 

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