Textbook not clear explain this question(s)

[viet_jon]

[SOLVED] Textbook not clear... please help explain this question(s)...

Question 1.

Homework Statement

State whether the limit exists for (Limit as x aproaches infinity ==> (n+1)/(n+1)

and give the value of it if it does exist. Graph the first 5 terms of each sequence.

The Attempt at a Solution

if you use any number for "n", numerator divided by denominator would equal 1.


Question 2:

Homework Statement

The sequence a1, a2, a3 ... has the following possible nth terms. For the case given below try various large values for n and guess the limit. Confirm that guess by manipulating the general term an.

a(n) = (n+1) / (n^2+1)I'm taking a intro Calc class, so this is probably easy stuff for you guys, that's why I lumped both questions into one thread. Anhow, I'm not looking for an answer since it's in my book, I just want to know what the question is asking for.

 

[viet_jon]

and... where's that thread that explains how to use syntax.edit: nm, I just found it...latex not syntax lol

 

[Dick]

So what's your question? Did you follow the suggestion and substitute various values of n? What's your guess of the limit?

 

[viet_jon]

question 1: limit equals 1?

 

[viet_jon]

question 2:


answer:

an = n + 1 / n^2 + 1

possible answers: 11/101, 101/10001, 1001/1000001 appears to have limit of zero?


but how does it have limit of zero?

 

[Dick]

Yep. Can you prove it? Divide numerator and denominator by n.

 

[Dick]

question 2:


answer:

an = n + 1 / n^2 + 1

possible answers: 11/101, 101/10001, 1001/1000001 appears to have limit of zero?


but how does it have limit of zero?

Same answer, yes. Can you prove it? Divide numerator and denominator by n^2.

 

[viet_jon]

oh wait...question 2's answer is from the book, not mine.

I attempted it the same way.....exceptwhat I don't understand is how it has a limit of zero?

 

[Dick]

Ok, divide numerator and denominator of 2) by n^2. This gives you (1/n+1/n^2)/(1+1/n^2), right? What's the limit of 1/n and 1/n^2?

 

[viet_jon]

wait...

the question is (n + 1) / (n^2 +1)

so divide num/denom by n^2 it should be(n/n^2) + (1/n^2) / (n^2/n^2) + (1/n^2) right?then it goes

(1/n) + (1/n^2) / 1 + (1/n^2)

then it goes, which is the step I don't understand...(0+0) / (1 + 0) = 0/1 = 0where are all these zero's coming from?

 

[Dick]

The limit of 1/n as n goes to infinity is zero. Likewise for 1/n^2. The numerator is 1 and the denominator gets larger and larger.

 

[viet_jon]

i just read this page http://en.wikiversity.org/wiki/Calculus/Limits

i get why now...

thnks DICK! :)