The 6.9 N weight is in equilibrium under the

[KB94]

Homework Statement

The 6.9 N weight is in equilibrium under the
influence of the three forces acting on it. The
F force acts from above on the left at an angle
of α with the horizontal. The 5.1 N force acts
from above on the right at an angle of 51◦ with
the horizontal. The force 6.9 N acts straight down.
What is the magnitude of the force F?
Answer in units of N.

Homework Equations

ΣF=0

The Attempt at a Solution

I broke the forces up into x and y components so:

ΣFy=6.9-5.1sin51°+Fsinα and ΣFx=5.1cos51°-Fcosα

What do I do now?

 

[rock.freak667]

The Attempt at a Solution

I broke the forces up into x and y components so:

ΣFy=6.9-5.1sin51°+Fsinα and ΣFx=5.1cos51°-Fcosα

What do I do now?

You know for equilibrium ΣF_y=0 and ΣF_x=0

So you have two equations with two unknowns, solve them and find the unknowns.