The acceleration of protons using a changing magnetic field

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Homework Help Overview

The discussion revolves around the acceleration of protons in a changing magnetic field, focusing on the relationship between magnetic and electric fields and their effects on particle motion. Participants explore concepts related to tangential acceleration and the forces acting on charged particles.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between magnetic fields and tangential acceleration, questioning how to calculate tangential acceleration and whether derivatives are involved. There are inquiries about relevant equations and the role of electric fields generated by changing magnetic fields.

Discussion Status

Guidance has been offered regarding the generation of electric fields from time-varying magnetic fields and their role in accelerating protons. Multiple interpretations of how magnetic and electric forces contribute to particle acceleration are being explored, with participants questioning the nature of these forces and their effects on velocity.

Contextual Notes

Some participants express uncertainty about the implications of magnetic forces on the speed of protons, noting that the magnetic force is perpendicular to the motion and questioning how it contributes to changes in speed.

Jaccobtw
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Homework Statement
In earlier learning sequences we described how a static magnetic field cannot change the speed (and therefore kinetic energy) of a free charged particle. A changing magnetic field can, and this is one way particle beams are accelerated. Consider free protons following a circular path in a uniform magnetic field with a radius of 1m. At t=0s, the magnitude of the uniform magnetic field begins to increase at 0.001T/s. Enter the tangential acceleration of the protons in m/s^2: positive if they speed up and negative if they slow down.
Relevant Equations
$$F = qvBsin\theta$$
$$ r = \frac{mv}{qB}$$
$$\Phi = \int B \cdot dA$$
If we increase the magnetic field, the radius of the particle's circular path will decrease which increases the tangential acceleration. How do I find the tangential acceleration. Do I use derivatives?
 
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Note that since ##\vec F_{mag} = q\vec v \times \vec B##, we necessarily have ##\vec F_{mag} \perp \vec v##. So, ##\vec F_{mag}## can't change the magnitude of ##\vec v##.

Are there other relevant equations needed?
A labeled diagram would help.
 
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A time varying magnetic field generates an electric field which will give the tangential acceleration to the protons. Use Faraday's law to calculate the magnitude of the generated electric field at r=1m.
The field lines of this electric field are concentric circles, centered at the origin, with their plane perpendicular to the uniform magnetic field.
 
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Delta2 said:
A time varying magnetic field generates an electric field which will give the tangential acceleration to the protons. Use Faraday's law to calculate the magnitude of the generated electric field at r=1m.
The field lines of this electric field are concentric circles, centered at the origin, with their plane perpendicular to the uniform magnetic field.
Thanks for the big hint!. The protons are accelerated by the electric field.
 
Jaccobtw said:
Thanks for the big hint!. The protons are accelerated by the electric field.

My hint was a little more subtle.
Note that, when the magnetic force is the only force,
the protons are accelerated by the magnetic field
since their velocity vectors are turned by the magnetic force.
 
robphy said:
My hint was a little more subtle.
Note that, when the magnetic force is the only force,
the protons are accelerated by the magnetic field
since their velocity vectors are turned by the magnetic force.
But doesn't the increasing tangential velocity only come from the electric field? The magnetic force is perpendicular to the proton's motion so it's speed can't increase from that, only direction can change.
 
Jaccobtw said:
But doesn't the increasing tangential velocity only come from the electric field? The magnetic force is perpendicular to the proton's motion so it's speed can't increase from that, only direction can change.
Yes, the speed changes because of the electric field,
but
##\vec a=\frac{d\vec v}{dt}## is a nonzero vector
when the magnitude of ##\vec v## changes, or the direction of ##\vec v## changes, or both.

This might be helpful:

 
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