The amount of radioactive substance after 38 days

In summary: In plain text, we do not have access to superscript and subscript to write out the equation in the more "correct" algebraic notation.In summary, we can choose the correct option without solving it by using the equations ##N = N_0 e^{- \lambda t}## and ##N = N_0 e^{- \frac {t} {t_{\frac 1 2}}}## to model exponential decay, where ##N_0## is the initial amount, ##t## is the time, and ##t_{\frac 1 2}## is the half-life. In this problem, after 38 days, the remaining amount is 0.01 grams, indicating that the correct option
  • #1
Pushoam
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Homework Statement


upload_2017-12-12_14-30-30.png


Homework Equations

The Attempt at a Solution



Is there anyway to choose the correct option without solving it?

## \lambda = \frac { 0.693 } { t_{\frac 1 2}} ##
[/B]
## N = N_0 e^{- 0.693 {\frac { t } { t_{\frac 1 2 }}}} ##

## N = 10.24 e^{- \frac { 0.693 * 38 } { 3.8} } = 10^{-2} ~ gm##So, the correct option is (b).

Is this correct?
 

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  • #2
Why the raised dot between those digits? If to mean decimal point, that is not the way to show it.
Half-life, 3.8 days;
Want how much after 38 days;
Begin with 10.24 grams

If model is for exponential decay, then A=10.24*e^(-k*t).
Find k using half-life information.
(1/2)=1*e^(-k*3.8)
(1/2)=e^(-3.8k)
ln(1/2)=ln(e^(-3.8k))
ln(1/2)=-3.8k*1
k=-ln(1/2)/3.8
k=ln(2)/3.8
k=0.1824

Revise for the more specific decay equation:
A=10.24*e^(-0.1824t)

How much remaining after 38 days?
Let t=38 and evaluate A.
 
  • #3
38 days is 10 half-lives. 2^10 = 1024. 10.24/1024 = 0.01.
 
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  • #4
symbolipoint said:
Why the raised dot between those digits? If to mean decimal point, that is not the way to show it.
It is the symbol of multiplication. Please, see the keyboard for this. You, too, have used it in the following expression,
symbolipoint said:
A=10.24*e^(-k*t).

symbolipoint said:
k=ln(2)/3.8
I have written ##\lambda## instead of k.
The above is nothing but, k = 0.693 /t½.
 
  • #5
Pushoam said:
It is the symbol of multiplication. Please, see the keyboard for this. You, too, have used it in the following expression,
I have written ##\lambda## instead of k.
The above is nothing but, k = 0.693 /t½.
I looked at the linked document you posted in the beginning post. There was a raised dot but that is to be used to signify multiplication. We want the character to be at the botton of the digits levels to read it as a decimal point. If I use a raised dot, I use it as a multiplication operation. That is the normal, common usage. The middle quoted passage shows the asterisk also often used for multiplication, and common and usually understood when using plain text to write an algebraic expression; it might appear as a raised dot, or it might appear exactly the asterisk. The 10.24 shows the decimal point, and the "three point eight" as the decimal number should be written as 3.8 (notice the dot at the bottom-level).
 
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1. What is the equation for calculating the amount of radioactive substance after 38 days?

The equation for calculating the amount of radioactive substance after 38 days is A = A₀ * e^(-λt), where A₀ is the initial amount of substance, λ is the decay constant, and t is the time elapsed.

2. How is the decay constant, λ, determined for a specific radioactive substance?

The decay constant, λ, is determined by the half-life of the substance, which is the amount of time it takes for half of the initial amount to decay. The formula for calculating λ is λ = ln(2) / t½, where t½ is the half-life of the substance.

3. Can the amount of radioactive substance after 38 days be predicted accurately?

Yes, the amount of radioactive substance after 38 days can be predicted accurately using the equation A = A₀ * e^(-λt). This equation takes into account the initial amount and the decay constant, which are both constant values for a specific substance.

4. How does the amount of radioactive substance change over time?

The amount of radioactive substance decreases over time due to radioactive decay. As the substance decays, it releases energy and transforms into a different element or isotope.

5. Are there any factors that can affect the amount of radioactive substance after 38 days?

The amount of radioactive substance after 38 days is affected by the initial amount of substance, the type of substance, and the decay constant. External factors such as temperature and pressure do not significantly impact the amount of substance after 38 days.

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