Radioactivity homework question

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Homework Help Overview

The problem involves calculating the activity of 239Pu produced in a nuclear power plant, specifically focusing on the decay constant and the relationship between the amount of substance and its activity in becquerels (Bq).

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the number of moles of 239Pu and subsequently the number of nuclei, but questions how to determine the decay constant without the half-life. Other participants discuss the need for reference materials to find the half-life.

Discussion Status

Participants are exploring the need for external resources to find the half-life of 239Pu, with some guidance provided on where to locate such information. There is an acknowledgment of the limitations faced without access to these tables.

Contextual Notes

The original poster is working under the assumption that the half-life is necessary for the calculations but does not have this information readily available, leading to confusion in their attempts.

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Homework Statement



A nuclear power plant breeds 1mg of 239Pu per week. What activity, in Bq, does that create?


Homework Equations



R_0 = \lambda N_0 (initial activity of the sample)

R = R_0 e^{-\lambda t} (exponential behavior of the decay rate)

T_{1/2}=\frac{ln 2}{\lambda} (Half-life)

The Attempt at a Solution



(a) First I find the number of moles in 1mg of 239Pu:

n= \frac{1\times10^{-3}}{239}=4.184 \times 10^{-6}

Now, I think to find N0 I have to times n by 6.02x1023 nuclei/mol. Which gives us N0=2.518x1018.

But how can I find the decay constant λ, if we are not given the half life? :confused:

I tried out the 1 week as the half life but I didn't get the correct answer:

\lambda = \frac{0.693}{604800 \ s} = 1.1458 \times 10^{-6}

R_0 = \lambda N_0 = 2.88 \times 10^{12} \ Bq

R = R_0 e^{-\lambda t} = 1.44 \times 10^{12}

So, what should I do? The correct answer must be: 2.3 \times 10^6 \ Bq.
 
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The half-life is usually something that you look up. Back in my time (:-P) we had a book of tables where you could find this, nowadays we have Wolfram Alpha.
 


Right, I see. So there's no equation or anything you can use in this situation if you don't have a table?
 

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