The Analytic Continuation of the Lerch and the Zeta Functions

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SUMMARY

The analytic continuations of the Lerch Transcendent and Riemann Zeta Functions are established using Euler’s Series Transformation and the E-process. The discussion highlights the role of Dirichlet Series as a foundational concept. While the continuations are presented, their convergence is not demonstrated. Basic knowledge of complex analysis and series manipulations is assumed for readers engaging with this topic.

PREREQUISITES
  • Complex analysis fundamentals
  • Understanding of series manipulations
  • Familiarity with Dirichlet Series
  • Knowledge of Euler’s Series Transformation
NEXT STEPS
  • Research the convergence criteria for series in complex analysis
  • Explore advanced techniques in analytic continuation
  • Study the properties and applications of the Riemann Zeta Function
  • Learn about the E-process and its generalizations
USEFUL FOR

Mathematicians, researchers in analytic number theory, and students studying complex analysis will benefit from this discussion.

benorin
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Introduction
In this brief Insight article the analytic continuations of the Lerch Transcendent and Riemann Zeta Functions are achieved via the Euler’s Series Transformation (zeta) and a generalization thereof, the E-process (Lerch). Dirichlet Series is mentioned as a steppingstone. The continuations are given but not shown to be convergent by any means, though if you the reader would be interested in such write me in the comments and I may oblige with an update if I get around to it. Some basic complex analysis and (double) series manipulations are the only assumed knowledge herein.
Euler’s Series Transformation and the E-Process
We wish to consider the supposed convergent alternating series ##\sum\limits_{k = 1}^\infty  {{{\left( { – 1} \right)}^{k – 1}}{a_k}} ## by use of the power series
$$f\left( x \right) = \sum\limits_{k = 1}^\infty  {{{\left( { – 1} \right)}^{k – 1}}{a_k}} {x^k}\text{     (1.1)  }$$
Which we require to converge for at least ## – 1 < x \leq 1## .  That we...

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