The AnswerUnderstanding Kirchhoff's Laws and Sign Conventions for RL Circuits

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Homework Help Overview

The discussion revolves around understanding Kirchhoff's laws as they apply to RL circuits, specifically focusing on the sign conventions used in the equations representing these laws.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster questions the sign conventions in the equations for RL circuits, suggesting an alternative formulation. Other participants discuss the implications of Kirchhoff's loop rule and the relationship between the inductor and resistor in terms of potential differences.

Discussion Status

Participants are exploring different interpretations of the sign conventions in Kirchhoff's laws for RL circuits. Some guidance has been offered regarding the direction of current and how it affects the signs of the potential differences across the components.

Contextual Notes

The discussion is constrained by the assumption that the RL circuit in question consists solely of a resistor and an inductor without a voltage source, which influences the application of Kirchhoff's laws.

cherev
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about kirchoff?

Homework Statement



can anybody explain why we write kirchhoff laws on RL circuit like

-Ldı/dt -iR=0

shouldn't it be written like

-Ldı/dt +iR=0



Homework Equations



-Ldı/dt -iR=0
-Ldı/dt +iR=0



it is about signs and how we know inductans' poles + or - while writing these equations
 
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maybe the inductor can be considered as a normal resisitor...therefore its written as -iR
 
Hi cherev,

From your equation, I guess your RL circuit is just a resistor and an inductor attached together (no voltage source).

In that case, Kirchoff's loop rule indicates that the magnitudes of the potential differences must be the same for the resistor and inductor, and that one must be positive and one must be negative. (That's the only way two potential differences would cancel as you travel around the loop.) Which one is positive and which one is negative depends on whether you go clockwise or counterclockwise around the loop.

So let's say we travel around the loop in the same direction as the current. Then the potential difference across the resistor is negative, and across the inductor is positive:

[tex] {V}_L -I R =0[/tex]

But [itex]V_L[/itex] is the back emf of the inductor, and is therefore [itex]V_L = -L (dI/dt)[/itex], giving your result.

If you go the other way around the loop, [itex]V_R=IR[/itex] is positive and [itex]V_L[/itex] is negative, which leads to the same result except with both terms positive.
 
thanks...!
 

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