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## Homework Statement

I have done an integration and ended up with the result

[-c/2 * [e^(-2x)]] |^infinity_0 = 1

The solution is that c=2 so that means to me that e^(2x) must turn into minus 1 for it to equal 1... but I'm not sure.. I've got graphcalc so I've been staring at the graph and I figure that as x goes to infinity that e^x goes to 1... but not sure what to say when x goes to minus infinity?